set.isdisjoint() method in Python

A set is disjoint to another set if  there are no elements in common between the two sets. This means that the intersection of the two sets is an empty set. 

For example, set {1, 3, 5} and {2, 4, 6} are disjoint because they don't have any common element(s).

The isdisjoint() method checks if the current set is disjoint with another set given as argument.

set_a.isdisjoint(set_b)

The method returns True if set_a has no common elements with set_b, else False.

set1 = {1, 3, 5, 7, 9}
set2 = {0, 2, 4, 6, 8}

#check if whether the two sets are disjoint
print(set1.isdisjoint(set2)) #True
print(set2.isdisjoint(set1)) #True

In the above case, the isdisjoint() method method returns True the two sets have no common elements. 

set1 = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} #digits
set2 = {1, 3, 5, 7, 9}#odds
set3 = {0, 2, 4, 6, 8}#evens

#check for disjoints
print(set1.isdisjoint(set2)) #False
print(set1.isdisjoint(set3)) #False

Using other iterables

As earlier mentioned, the iterable given as argument does not necessarily have to be a set. It can be any iterable object.

integers = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} #digits

odds = [1, 3, 5, 7, 9] # a list
evens = [0, 2, 4, 6, 8] # a list

#check for disjoints
print(integers.isdisjoint(odds)) #False
print(integers.isdisjoint(evens)) #False
print(integers.isdisjoint([-1, -2, -3, -4, -5])) #True